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  <title>Weiqi Gao&#039;s Observations - math tag</title>
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    <title>Friday Math Quiz: Show That ...</title>
    <link>http://www.weiqigao.com/blog/2010/12/17/friday_math_quiz_show_that.html</link>
    
      
        <description>
          &lt;p&gt;I went to a mini-reunion with a few friends from my high school class up in Chicago last weekend (and got caught in the blizzard on the way back, but that&#039;s another story.)&lt;/p&gt;

&lt;p&gt;I was reminded of the math that we did in high school, and what fun and challenge it was.  Here&#039;s a problem from ninth grade:&lt;/p&gt;

&lt;p&gt;&lt;b&gt;Q&lt;/b&gt;: Given&lt;/p&gt;
&lt;p style=&#034;margin-left:3em;font-size:larger&#034;&gt;&lt;i&gt;&lt;t&gt;x&lt;sup&gt;&lt;small&gt;2&lt;/small&gt;&lt;/sup&gt; + y&lt;sup&gt;&lt;small&gt;2&lt;/small&gt;&lt;/sup&gt; &amp;le; 1&lt;/t&gt;&lt;/i&gt;,&lt;/p&gt;
&lt;p&gt;show that&lt;/p&gt;
&lt;p style=&#034;margin-left:3em;font-size:larger&#034;&gt;&lt;i&gt;&lt;t&gt;|x&lt;sup&gt;&lt;small&gt;2&lt;/small&gt;&lt;/sup&gt; + 2 x y - y&lt;sup&gt;&lt;small&gt;2&lt;/small&gt;&lt;/sup&gt;| &amp;le; &lt;big&gt;&amp;radic;&lt;/big&gt;&lt;span style=&#034;text-decoration:overline;&#034;&gt;&amp;nbsp;2 &amp;nbsp;&lt;/span&gt;&lt;/t&gt;&lt;/i&gt;.
&lt;/p&gt;

&lt;p&gt;Can your ninth grader solve this problem?&lt;/p&gt;
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    <pubDate>Fri, 17 Dec 2010 13:34:50 GMT</pubDate>
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    <title>High School Mathematics Education</title>
    <link>http://www.weiqigao.com/blog/2008/03/18/high_school_mathematics_education.html</link>
    
      
        <description>
          &lt;p&gt;The state of high school education is a hot topic among some of my friends and colleagues.  I have heard older people say that the US high school education, especially mathematics and sciences, has declined considerably over the past fifty years.  I&#039;ve also heard people who received high school education from a different part of the world and also experienced indirectly the US system, either through their children going through it, or through their contact with graduates of the system, that the level of US mathematics and sciences education is not as high as in other countries.&lt;/p&gt;

&lt;p&gt;The counter argument of course is that when such generalized statements are made, they are only anecdotal and are not backed up by statistics or any kind of research data.&lt;/p&gt;

&lt;p&gt;I went on the internet (of course the internet knows it all) in search of any evidence that will support either side of the argument.  Alas, I couldn&#039;t find any concrete evidence either.  But I did find the following items:&lt;/p&gt;

&lt;ul&gt;
&lt;li&gt;A US documentary film named &lt;a href= &#034;http://www.2mminutes.com/&#034; &gt;Two Million Minutes&lt;/a&gt; that followed six high school students in the United States, China, and India&lt;/li&gt;
&lt;li&gt;Some &lt;a href= &#034;http://edu.sina.com.cn/shiti/2007/1108/225603698.html&#034; &gt;Chinese high school mathematics tests&lt;/a&gt;.  This is a district wide midterm for the first semester of High-3.  (The Chinese system goes E1-E6, M1-M3 and H1-H3, so H3 is roughly equivalent to 12th grade in the US)&lt;/li&gt;
&lt;/ul&gt;

&lt;p&gt;I haven&#039;t see the documentary myself, but am fascinated by some of the discussions on their blog, especially by the contrast between the reactions from ordinary people and those from US educators.&lt;/p&gt;

&lt;p&gt;As for the Chinese high school mathematics test, here is one of the problems translated into English:&lt;/p&gt;

&lt;p style=&#034;margin-left:3em&#034;&gt;&lt;b&gt;(16) (This problem is worth 13 points)&lt;br/&gt;&lt;br/&gt;

Given the function &lt;i&gt;f(x) = x + 4 / x &lt;sup&gt;2&lt;/sup&gt;&lt;/i&gt;.&lt;br/&gt;&lt;br/&gt;

(I) Find the interval over which &lt;i&gt;f(x)&lt;/i&gt; is monotonically decreasing;&lt;br/&gt;
(II) Find the maximum and the minimum of &lt;i&gt;f(x)&lt;/i&gt; when &lt;i&gt;x &amp;epsilon; [1, 4]&lt;/i&gt;.&lt;/b&gt;&lt;/p&gt;

&lt;p&gt;Keep in mind that this is part of a 120-minute test consisting of 20 problems worth a total of 150 points.  So the students have about 10 minutes to finish the problem.&lt;/p&gt;

&lt;ul&gt;
&lt;li&gt;Can your high school senior correctly solve the problem in the allotted time?&lt;/li&gt;
&lt;li&gt;Is this problem on par in difficulty with the ones your high school senior get from school?&lt;/li&gt;
&lt;li&gt;What if you are not from the US or China?  Is the problem easier or harder than your typical assignments?&lt;/li&gt;
&lt;li&gt;What if you are from way back when?  50&#039;s? 60&#039;s? 70&#039;s? 80&#039;s? 90&#039;s?  Is this comparable to what you have to go through?&lt;/li&gt;
&lt;/ul&gt;
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    <pubDate>Wed, 19 Mar 2008 00:20:22 GMT</pubDate>
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    <title>Real World Arithmetic On The Abacus, Part III: Division</title>
    <link>http://www.weiqigao.com/blog/2006/10/05/real_world_arithmetic_on_the_abacus_part_iii_division.html</link>
    
      
        <description>
          &lt;p&gt;Continuing with the abacus theme &lt;a href= &#034;http://www.weiqigao.com/blog/2006/10/03/real_world_arithmetic_on_the_abacus_part_ii_subtraction_multiplication.html&#034; &gt;two&lt;/a&gt; and &lt;a href= &#034;http://www.weiqigao.com/blog/2006/10/03/real_world_arithmetic_on_the_abacus_part_i_addition.html&#034; &gt;three&lt;/a&gt; days ago, we move on the division today.  (You can compare my traditional approach to &lt;a href= &#034;http://scienceblogs.com/goodmath/2006/09/division_on_the_abacus.php&#034; &gt;MarkCC&#039;s approach&lt;/a&gt;.)&lt;/p&gt;

&lt;h4&gt;Division&lt;/h4&gt;

&lt;p&gt;Abacus division is the inverse of abacus multiplication in a lot of ways: in multiplication, the second factor is placed flush left. in division the divisor is placed flush left.  In multiplication, the first factor is placed near the right end of the abacus leaving a space just wide enough to hold the second factor, and when we are done, the result is flush right.  In division, the dividend is placed flush right, and when we are done, the result&#039;s unit digit floats to the left.  If the dividend is an integral multiple of the divisor, there would have been a space to the right of the result that&#039;s as wide as the divisor.  In other words, with multiplication, the decimal point floats to the right; and with division, it floats to the left.&lt;/p&gt;

&lt;p&gt;As with pencil and paper division, you start the division my dividing the first digit of the divisor into the first digit of the dividend and obtain a tentative first digit of the quotient.  You then multiply the divisor by the tentative quotient digit and subtract the result from the dividend.  When this is done, you move to the next digit of the dividend and repeat the process.&lt;/p&gt;

&lt;p&gt;Here are the division rhymes:&lt;/p&gt;

&lt;p style=&#034;margin-left:3em&#034;&gt;see one advance one&lt;br/&gt;
see two advance two&lt;br/&gt;
see three advance three&lt;br/&gt;
see four advance four&lt;br/&gt;
see five advance five&lt;br/&gt;
see six advance six&lt;br/&gt;
see seven advance seven&lt;br/&gt;
see eight advance eight&lt;br/&gt;
see nine advance nine&lt;br/&gt;
&lt;br/&gt;
two one turn to five&lt;br/&gt;
see two advance one&lt;br/&gt;
see four advance two&lt;br/&gt;
see six advance three&lt;br/&gt;
see eight advance four&lt;br/&gt;
&lt;br/&gt;
three one three leave one&lt;br/&gt;
three two six leave two&lt;br/&gt;
see three advance one&lt;br/&gt;
see six advance two&lt;br/&gt;
see nine advance three&lt;br/&gt;
&lt;br/&gt;
four one two leave two&lt;br/&gt;
four two turn to five&lt;br/&gt;
four three seven leave two&lt;br/&gt;
see four advance one&lt;br/&gt;
see eight advance two&lt;br/&gt;
&lt;br/&gt;
five one double as two&lt;br/&gt;
five two double as four&lt;br/&gt;
five three double as six&lt;br/&gt;
five four double as eight&lt;br/&gt;
see five advance one&lt;br/&gt;
&lt;br/&gt;
six one next add four&lt;br/&gt;
six two three leave two&lt;br/&gt;
six three turn to five&lt;br/&gt;
six four six leave four&lt;br/&gt;
six five seven leave two&lt;br/&gt;
see six advance one&lt;br/&gt;
&lt;br/&gt;
seven one next add three&lt;br/&gt;
seven two next add six&lt;br/&gt;
seven three four leave two&lt;br/&gt;
seven four five leave five&lt;br/&gt;
seven five seven leave one&lt;br/&gt;
seven six eight leave four&lt;br/&gt;
see seven advance one&lt;br/&gt;
&lt;br/&gt;
eight one next add two&lt;br/&gt;
eight two next add four&lt;br/&gt;
eight three next add six&lt;br/&gt;
eight four turn to five&lt;br/&gt;
eight five six leave two&lt;br/&gt;
eight six seven leave four&lt;br/&gt;
eight seven eight leave six&lt;br/&gt;
see eight advance one&lt;br/&gt;
&lt;br/&gt;
nine one next add one&lt;br/&gt;
nine two next add two&lt;br/&gt;
nine three next add three&lt;br/&gt;
nine four next add four&lt;br/&gt;
nine five next add five&lt;br/&gt;
nine six next add six&lt;br/&gt;
nine seven next add seven&lt;br/&gt;
nine eight next add eight&lt;br/&gt;
see nine advance one&lt;/p&gt;

&lt;p&gt;That&#039;s a lot of lines to memorize.  And they pretty much are useless unless you are using an abacus.  But when you are six or seven or eight years old, it&#039;s really not that big a deal.  (I was able to recite 10000-word essays out of memory, too, when I was six.)&lt;/p&gt;

&lt;p&gt;Here&#039;s how they work:&lt;/p&gt;

&lt;p&gt;Each groups of lines handle one one digit divisor.  The first group of lines are used when dividing a number by two, etc.&lt;/p&gt;

&lt;p&gt;The lines of the form &#034;see k*d advance k&#034; is the easiest to carry out.  Take the &#034;see six advance three&#034; line from the &#034;divide by two&#034; group as an example.  It means if you see a six, you should take away that six and add three to the digit on the left.  The result? 6 &amp;divide; 2 = 3.  What about 7 &amp;divide; 2?  Well you can still use &#034;see six advance three&#034;.  You take away six in the current digit and put a three on the digit to the left.  There will be a one left on the current digit.  And that&#039;s when the &#034;two one turn to five&#034; line gets applied.  It literally means that you should turn that one into a five.  This gives you 7 &amp;divide; 2 = 3.5.  (Remember the decimal floats to the left by one digit when you divide by two, a one digit number.)&lt;/p&gt;

&lt;p&gt;In general, the &#034;2k k turn to five&#034; lines: two one turn to five, four two turn to five, six three turn to five, and eight four turn to five, corresponds to 1 &amp;divide; 2 = 0.5, 2 &amp;divide; 4 = 0.5, 3 &amp;divide; 6 = 0.5, and 4 &amp;divide; 8 = 0.5.&lt;/p&gt;

&lt;p&gt;The set of lines of the form &#034;d n m leave r&#034; all satisfy the equation 10n = d * m + r.  It corresponds to the action, when dividing by d, that if you see n, you should change it into an m and add r to the digit on the right.  Thus &#034;three one three leave one&#034; is used when dividing 3 into 1.  You literally turn that 1 into a 3 and add 1 to the next digit.  If you extend the abacus to have infinite length, then you can keep on applying &#034;three one three leave one&#034; to the 1 that you have just added, turning it into a 3 and add a 1 to the right.  This way you get the repeat decimal result 1 &amp;divide; 3 = 0.333333...&lt;/p&gt;

&lt;p&gt;The lines &#034;d n next add r&#034; are degenerate forms of &#034;d n n leave r.&#034;  Since the would be quotient is the same as the dividend digit, you don&#039;t have to do any thing to that digit.  You can just add the remainder to the next digit.&lt;/p&gt;

&lt;p&gt;OK.  Let&#039;s apply what we learned so far to the division 1000000 &amp;divide; 7:&lt;/p&gt;

&lt;pre style=&#034;margin-left:3em&#034;&gt;
7     1000000|
7     1&lt;span style=&#034;color:red&#034;&gt;3&lt;/span&gt;00000|  seven one next add three
7     1&lt;span style=&#034;color:red&#034;&gt;42&lt;/span&gt;0000|  seven three four leave two
7     142&lt;span style=&#034;color:red&#034;&gt;6&lt;/span&gt;000|  seven two next add six
7     142&lt;span style=&#034;color:red&#034;&gt;84&lt;/span&gt;00|  seven six eight leave four
7     1428&lt;span style=&#034;color:red&#034;&gt;55&lt;/span&gt;0|  seven four five leave five
7     14285&lt;span style=&#034;color:red&#034;&gt;71&lt;/span&gt;|  seven five seven leave one&lt;/pre&gt;

&lt;p&gt;Therefore 1000000 &amp;divide; 7 = 142857 with a remainder of 1.  And if you paid attention, you realize that the pattern will repeat indefinitely if we had an infinite abacus.  BTW, 142857 is one of those numbers that show up in math quizzes because its multiples are also its decimal circular shifts:&lt;/p&gt;

&lt;p style=&#034;margin-left:3em&#034;&gt;142857 * 2 = 285714&lt;br/&gt;
142857 * 3 = 428571&lt;br/&gt;
142857 * 4 = 571428&lt;br/&gt;
142857 * 5 = 714285&lt;br/&gt;
142857 * 6 = 857142&lt;/p&gt;

&lt;p&gt;The only remaining lines are the divide-by-five ones: five one double as two, five two double as four, five three double as six, five four double as eight.  When dividing by 5, you simply double all digits that are less than five.  For digits greater then five, one application of &#034;see five advance one&#034; will reduce it to less than five.&lt;/p&gt;

&lt;p&gt;Fun exercises for division include the 123456789 &amp;divide; n, where n is 2, 3, 4, 5, 6, 7, 8, 9.&lt;/p&gt;

&lt;p&gt;So far, all of our divisors are single digit.  Things gets a little bit complicated when we have multiple digit divisors.  Unlike single digit division, where the tentative quotient is always the true quotient, in multiple digit division, there is a chance that the tentative quotient is too big.  For example, when divide 40 by 19, the tentative quotient is 4 &amp;divide; 1 = 4, which is too big (the real quotient is 2.)  A mechanism exists to return one unit of the tentative quotient to the dividend.  The rhymes are:&lt;/p&gt;

&lt;p style=&#034;margin-left:3em&#034;&gt;one withdraw one return one&lt;br/&gt;
two withdraw one return two&lt;br/&gt;
three withdraw one return three&lt;br/&gt;
four withdraw one return four&lt;br/&gt;
five withdraw one return five&lt;br/&gt;
six withdraw one return six&lt;br/&gt;
seven withdraw one return seven&lt;br/&gt;
eight withdraw one return eight&lt;br/&gt;
nine withdraw one return nine&lt;/p&gt;

&lt;p&gt;Note that the division rhymes already take care of subtracting the product of the quotient and the first digit of the divisor from the dividend, we only need to subtract the product of the rest of the digits and the quotient from the dividend.  Here&#039;s a worked example of 87 &amp;divide; 27 = 3 with a remainder of 6:&lt;/p&gt;

&lt;pre style=&#034;margin-left:3em&#034;&gt;27         87|
27        &lt;span style=&#034;color:red&#034;&gt;40&lt;/span&gt;7| see eight advance four, but 4 * 7 = 28 &gt; 07
27        &lt;span style=&#034;color:red&#034;&gt;32&lt;/span&gt;7| two withdraw one return two
27        3&lt;span style=&#034;color:red&#034;&gt;06&lt;/span&gt;| 3 * 7 = 21, 27 - 21 = 06&lt;/pre&gt; 
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    <pubDate>Fri, 06 Oct 2006 04:59:37 GMT</pubDate>
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